BitrixAQA.General.Pop.GetAttachmentMsg C# (CSharp) Method

        public static bool GetAttachmentMsg(string hostname, int port, bool useSsl, string userEmail, string Password, string Subject, string AttachmentName)
        {
            try
            {
                using (Pop3Client client = new Pop3Client())
                {

                    client.Connect(hostname, port, useSsl);
                    client.Authenticate(userEmail, Password);

                    int messageCount = client.GetMessageCount();
                    List<OpenPop.Mime.Message> allMessages = new List<OpenPop.Mime.Message>(messageCount);

                    Regex rgx = new Regex(Subject, RegexOptions.IgnoreCase | RegexOptions.Compiled | RegexOptions.CultureInvariant);

                    for (int i = 1; i <= messageCount; i++)
                    {
                        Match match = rgx.Match(client.GetMessage(i).Headers.Subject);
                        //проверяем тему письма, если та что нам надо,ищем вложение
                        if (match.Success)
                        {
                            foreach (MessagePart Attachment in client.GetMessage(i).FindAllAttachments())
                                if (Attachment.FileName == AttachmentName.Split('\\')[AttachmentName.Split('\\').Length - 1])
                                    return true;
                        }
                    }
                    return false;
                }
            }
            catch (Exception ex)
            {
                Log.MesQuestion("Скорее всего превышено количество запросов");
                Log.MesQuestion(ex.Message);
                return false;
            }
        }