Bike.Parser.Lexer.Ampersand C# (CSharp) Method

        private Token Ampersand()
        {
            Match('&');
            Match('&');
            if (currentChar == '=')
            {
                Match('=');
                return Token(TokenType.OpAssign, "&&=");
            }
            return Token(TokenType.LogicalAnd, "&&");
        }