AbstractToYield.Async.Return C# (CSharp) Method

        private static string Return(
            [CallerMemberName] string memberName = "",
            [CallerFilePath] string filePath = "",
            [CallerLineNumber] int lineNumber = 0)
        {
            return "Returned from {0}\n{1} @ line {2}".FormatWith(memberName, filePath, lineNumber);
        }