ATMLModelLibrary.model.ProjectInfo.Deserialize C# (CSharp) Method

Deserialize() public static method

public static Deserialize ( string input ) : ProjectInfo
input string
return ProjectInfo
        public static ProjectInfo Deserialize(string input)
        {
            StringReader stringReader = null;
            try
            {
                var serializer = new XmlSerializer(typeof (ProjectInfo));
                stringReader = new StringReader(input.Replace('\0', ' ' ).Trim() );
                return ((ProjectInfo) (serializer.Deserialize(XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }