ATMLModelLibrary.model.signal.basic.Control.Deserialize C# (CSharp) Method

Deserialize() public static method

public static Deserialize ( string input ) : Control
input string
return Control
        public new static Control Deserialize(string input)
        {
            System.IO.StringReader stringReader = null;
            try
            {
                stringReader = new System.IO.StringReader(input);
                return ((Control)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }

Same methods

Control::Deserialize ( System s ) : Control
Control::Deserialize ( string input, Control &obj ) : bool
Control::Deserialize ( string input, Control &obj, System &exception ) : bool