SuperMap.Web.ISDotNET6.ShowBusLineResult.FromJson C# (CSharp) 메소드

FromJson() 공개 정적인 메소드

${IS6_ShowBusLineResult_method_fromJSON_D}
public static FromJson ( System.Json.JsonObject json ) : ShowBusLineResult
json System.Json.JsonObject ${IS6_ShowBusLineResult_method_fromJSON_param}
리턴 ShowBusLineResult
        public static ShowBusLineResult FromJson(JsonObject json)
        {
            if (json != null)
            {
                return new ShowBusLineResult { BusLine = BusLine.FromJson(json) };
            }
            return null;
        }