ServiceClientGenerator.SolutionFileCreator.ServiceProjectFromFile C# (CSharp) 메소드

        Project ServiceProjectFromFile(string folderName, string projectFile)
        {
            var fi = new FileInfo(projectFile);
            var projectName = Path.GetFileNameWithoutExtension(fi.Name);
            return new Project
            {
                Name = Path.GetFileNameWithoutExtension(projectFile),
                ProjectGuid = this._allProjects[projectName].ProjectGuid,
                ProjectPath = string.Format(@"src\Services\{0}\{1}", folderName, fi.Name)
            };
        }