Meyn.TestLink.TestLink.GetProject C# (CSharp) 메소드

        public TestProject GetProject(string projectname)
        {
            TestProject result = null;
            stateIsValid();
            object o = proxy.getTestProjectByName(devkey, projectname);
            handleErrorMessage(o);
            if (o is object[]) {
                object[] olist = o as object[];
                result = new TestProject(olist[0] as XmlRpcStruct);
            } else
                result = new TestProject(o as XmlRpcStruct);
            return result;
        }