TsRemux.TsRemux.OpenOutputFileDialog_FileOk C# (CSharp) Method

        private void OpenOutputFileDialog_FileOk(object sender, CancelEventArgs e)
        {
            if (string.CompareOrdinal(InputFileTextBox.Text, OpenOutputFileDialog.FileName) == 0)
            {
                OutputFileTextBox.Text = String.Empty;
                MessageBox.Show("Cannot open the same file as a source and an output file");
            }
            else
            {
                OutputFileTextBox.Text = OpenOutputFileDialog.FileName;
                RemuxButton.Enabled = true;
            }
        }