System.Xml.Schema.DatatypeImplementation.GetTypeName C# (CSharp) Méthode

        internal string GetTypeName()
        {
            XmlSchemaType simpleType = _parentSchemaType;
            string typeName;
            if (simpleType == null || simpleType.QualifiedName.IsEmpty)
            { //If no QName, get typecode, no line info since it is not pertinent without file name
                typeName = TypeCodeString;
            }
            else
            {
                typeName = simpleType.QualifiedName.ToString();
            }
            return typeName;
        }