BatchGuy.App.CreateX264BatchFileForm.btnOpenX264BatchFileOutputDialog_Click C# (CSharp) Méthode

        private void btnOpenX264BatchFileOutputDialog_Click(object sender, EventArgs e)
        {
            try
            {
                this.HandleBtnOpenX264BatchFileOutputDialogClick();
            }
            catch (Exception ex)
            {
                _displayErrorMessageService.DisplayError(new ErrorMessage() { DisplayMessage = "There was a problem opening up the file path!", DisplayTitle = "Error.", Exception = ex, MethodNameWhereExceptionOccurred = MethodBase.GetCurrentMethod().Name });
            }
        }