cn.jpush.api.push.mode.PushPayload.FromJSON C# (CSharp) Method

FromJSON() public static method

It need to have a notification or message.
public static FromJSON ( String payloadString ) : PushPayload
payloadString String
return PushPayload
        public static PushPayload FromJSON(String payloadString)
        {
            try
            {
                var jSetting = new JsonSerializerSettings();
                jSetting.NullValueHandling = NullValueHandling.Ignore;
                jSetting.DefaultValueHandling = DefaultValueHandling.Ignore;

                var jsonObject = JsonConvert.DeserializeObject<PushPayload>(payloadString, jSetting);
                return jsonObject.Check();
            }
            catch (Exception e)
            {
                Console.WriteLine("JSON to PushPayLoad occur error:" + e.Message);
                return null;
            }
        }