TriangleNet.NewLocation.LongestShortestEdge C# (CSharp) Method

LongestShortestEdge() private method

Given square of edge lengths of a triangle, determine its orientation
private LongestShortestEdge ( double aodist, double dadist, double dodist ) : int
aodist double
dadist double
dodist double
return int
        private int LongestShortestEdge(double aodist, double dadist, double dodist)
        {
            // 123: shortest: aodist	// 213: shortest: dadist	// 312: shortest: dodist
            //	middle: dadist 		//	middle: aodist 		//	middle: aodist
            //	longest: dodist		//	longest: dodist		//	longest: dadist
            // 132: shortest: aodist 	// 231: shortest: dadist 	// 321: shortest: dodist
            //	middle: dodist 		//	middle: dodist 		//	middle: dadist
            //	longest: dadist		//	longest: aodist		//	longest: aodist

            int max = 0, min = 0, mid = 0, minMidMax;
            if (dodist < aodist && dodist < dadist)
            {
                min = 3; // apex is the smallest angle, dodist is the longest edge
                if (aodist < dadist)
                {
                    max = 2; // dadist is the longest edge
                    mid = 1; // aodist is the middle longest edge
                }
                else
                {
                    max = 1; // aodist is the longest edge
                    mid = 2; // dadist is the middle longest edge
                }
            }
            else if (aodist < dadist)
            {
                min = 1; // dest is the smallest angle, aodist is the biggest edge
                if (dodist < dadist)
                {
                    max = 2; // dadist is the longest edge
                    mid = 3; // dodist is the middle longest edge
                }
                else
                {
                    max = 3; // dodist is the longest edge
                    mid = 2; // dadist is the middle longest edge
                }
            }
            else
            {
                min = 2; // origin is the smallest angle, dadist is the biggest edge
                if (aodist < dodist)
                {
                    max = 3; // dodist is the longest edge
                    mid = 1; // aodist is the middle longest edge
                }
                else
                {
                    max = 1; // aodist is the longest edge
                    mid = 3; // dodist is the middle longest edge
                }
            }
            minMidMax = min * 100 + mid * 10 + max;
            // HANDLE ISOSCELES TRIANGLE CASE
            return minMidMax;
        }