ATMLModelLibrary.model.signal.basic.Source.Deserialize C# (CSharp) Method

Deserialize() public static method

public static Deserialize ( string input, Source &obj ) : bool
input string
obj Source
return bool
        public static bool Deserialize(string input, out Source obj)
        {
            System.Exception exception;
            return Deserialize(input, out obj, out exception);
        }

Same methods

Source::Deserialize ( System s ) : Source
Source::Deserialize ( string input ) : Source
Source::Deserialize ( string input, Source &obj, System &exception ) : bool