ThoughtWorks.VisualStudio.Card.AddCardAttributeFilterToPostData C# (CSharp) Method

        internal void AddCardAttributeFilterToPostData(string name, string value)
        {
            MingleCard.PostData.Add(string.Format(CultureInfo.InvariantCulture,"card[{0}]={1}", name, value).Trim());
        }

        /// <summary>
        /// Calls MingleCard.Update() to update the card with contents of the text box.
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void OnPropertyTextBoxLostFocus(object sender, RoutedEventArgs e)
        {
            e.Source = _thisCard;
            string me = new StackFrame().GetMethod().Name;

            var tb = sender as TextBox;

            if (tb.Text == tb.Tag as string)
            {
                e.Handled = true;
                return;
            }
            switch (tb.DataContext.GetType().Name)
            {
            case "Card":
                // The name of the field is "cardXXXXXX", so we strip the "card" prefix from the
                // name of the TextBox.
                _thisCard.AddCardAttributeFilterToPostData(
                    tb.Name.Replace("card", string.Empty).ToLowerInvariant(), tb.Text);
                break;

            case "CardProperty":
                // The DataContext of the TextBox is a MinglePropertyDefinition object. So, we
                // take its name and pass it over to AddPropertyPostData.
                _thisCard.AddPropertyFilterToPostData((tb.DataContext as CardProperty).Name, tb.Text);
                break;
            }
            try
            {
                if (!string.IsNullOrEmpty(cardName.Text))
                {
                    _thisCard.Update();
                    descriptionBrowser.Refresh();
                }
                else
                {
                    MessageBox.Show(ThoughtWorksCoreLib.Resources.MingleCardNameNullOrEmpty);
                }
            }
            catch (Exception ex)
            {
                TraceLog.Exception(me, ex);
                MessageBox.Show(ex.Message);
            }

            e.Handled = true;
        }