ATMLModelLibrary.model.equipment.Resource.Deserialize C# (CSharp) Method

Deserialize() public static method

public static Deserialize ( string input, Resource &obj ) : bool
input string
obj Resource
return bool
        public static bool Deserialize(string input, out Resource obj)
        {
            Exception exception;
            return Deserialize(input, out obj, out exception);
        }

Same methods

Resource::Deserialize ( Stream s ) : Resource
Resource::Deserialize ( string input ) : Resource
Resource::Deserialize ( string input, Resource &obj, Exception &exception ) : bool